What is the equation of the line that passes through the given point and is perpendicular to the given line? Point: (1,1)
Line: y=15x+45

y= -1/15x + 16/15

Step-by-step explanation:

When two lines are perpendicular to each other that means their slopes are the negative reciprocals of each other.

So that means if a line has has a slope of 6, a line perpendicular to that line will have a slope of -1/6.

(a reciprocal is when the fraction is flipped over)

In this case, the negative reciprocal of 15 would be -1/15. So the slope of the line that is perpendicular would be -1/15.

The equation we would have so far for that line would be: y=-1/15x+b

Now we have to find the 'b' or the y intercept, which we can get by plugging in the point that was given (1,1), which is on that line.

Which gives us 1=-1/15(1)+b.

1=-1/15+b

1+1/15=b

Then you solve for b and get b= 16/15.

The equation of the line that is perpendicular to the given line is y= -1/15x + 16/15.

1.4

2.3

step-by-step explanation:

the formula for the constant of variation is

y= kx

divide each side by x

y/x =kx/x

y/x =k

we know a and y

1.   y/x = k

4/1 =4

check the other values to make sure they are the same

8/2 = 4   12/3 =4   and 16/4 =4  

the constant of variation is 4

2.   y/x = k

3/1 =3

check the other values to make sure they are the same

6/2 = 3   9/3 =3   and 12/4 =3  

the constant of variation is 3

what is the question? i am guessing you are looking for the area.

to find an area, you have to do length x width.

in this case, it would be 12 ft x 4 ft = 48 sq. ft