In a floor plan, the length, l, of a rectangular room is twice its width, w. The perimeter of the room must be greater than 72 feet. Which inequality can be used to find all possible widths of the room, in feet?

A. 6w > 72
B. 6w < 72
C. 3w > 72
D. 3w < 72

here the number -5 is all of the following except a rational number.

step-by-step explanation:

d.192

step-by-step explanation:

12*16=192

2 over 5

step-by-step explanation:

the 2: 3 ratio is the length of the ac segment to the cb segment total length. this implies that the ratio between segment ac length and segment ab length is 2: 5. point c is 2/5 from a to b, so the required fraction is 2/5.

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine