Matthew participates in a study that is looking at how confident students at SUNY Albany are. The mean score on the scale is 50. The distribution has a standard deviation of 10 and is normally distributed. Matthew scores a 65. What percentage of people could be expected to score the same as Matthew or higher on this scale

The percentage of people that could be expected to score the same as Matthew or higher on this scale is:

= 93.3%.

Step-by-step explanation:

a) Data and Calculations:

Mean score on the scale, μ = 50

Distribution's standard deviation, σ = 10

Matthew scores, x = 65

Calculating the Z-score:

Z-score = (x – μ) / σ

= (65-50)/10

= 1.5

The probability based on a Z-score of 1.5 is 0.93319

Therefore, the percentage of people that could be expected to score the same as Matthew or higher on this scale is 93.3%.

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

mean, 40.6

step-by-step explanation: