A box contains 5 white balls, 3 black balls, and 2 red balls. A-What is the probability of drawing a white ball?B- How many white balls must be added to the box so that the probability of drawing a white ball is 3/4?C-How many black balls must be added to the original assortment so that the probability of drawing a white ball is 1/4?

(b) 10 additional white balls

(c) 10 additional black balls

Step-by-step explanation:

Given

Solving (a): P(White)

This is calculated as:

Solving (b): Additional white balls, if

Let the additional white balls be x

So:

This gives:

Cross multiply

Collect like terms

Hence, 10 additional white balls must be added

Solving (c): Additional black balls, if

Let the additional black balls be x

So:

So, we have:

Cross multiply

Collect like terms

Hence, 10 additional black balls must be added

y = 2x

step-by-step explanation:

if you divide each number in the sequence, you'll see that they all have a multiple factor of 2. each number in the series, and any other numbers which may continue, will be multiplied by 2. therefore, y is the next number in the sequence, and x is the current one, so, our formula will be y = 2x.