How do i solve this

it’s geometry

x=5, y=11

Step-by-step explanation:

> sum of interior angles of a polygon is (n-2)·180°, where n-is the number of sides, so our rhombus has sum of angles =(4-2)·180° =360°

>we know that the opposite angles are congruent so ...

>we have the sum of interior angles is

108+108+7y-5+7y-5 = 360, combine like terms

14y +206 =360, subtract 206 from both sides

14y = 154, divide both sides by 14

y= 11

>the sides are congruent therefore

4x+17 = 8x-3 , subtract 4x, and add 3 from both sides

17+3 =8x-4x, combine like terms

20 = 4x , divide by 4 both sides

5 =x

sec ф = 5/3 (quadrant 4)

let x = base

y = perp

z = hypotenuse

sec ф = hypotenuse/base = 5/3

⇒ z = 5 and x = 3

finding y:

z² = x² + y²

5² = 3² + y²

y² = 25-9

y² = 16

y = 4

now finding all other geometric functions of theta:

sin ф = y/z = 4/5

sin ф = -4/5 (sin is negative in the 4th quadrant)

cos ф = x/z = 3/5

cos ф = 3/5 (cos is positive in 4th quadrant)

tan ф = y/x = 4/3

tan ф = -4/3 (tan is negative in 4th quadrant)

cosec ф = z/y = 5/4

cosec ф = -5/4 (cosec is negative in the 4th quadrant)

cot ф = x/y = 3/4

tan ф = -3/4 (tan is negative in 4th quadrant)

answer: give more info

step-by-step explanation: