This assignment has a value of 10 points. You will have two (2) questions to answer and one (1) attempt to send this assignment. Refer to the calendar in Blackboard for due dates. Your calendar is available under the Tools menu > Calendar. Once you have built the Excel tables, with all the changes in different tables, and answered all the questions you have to send the work (Excel sheets and answered questions) to the professor using the Attach File function in Black Board to attach your document and send it to the professor. To use the Attach File enter the Course Content in Black Board. Select the Assignment Module 5, attach the file and submit. Solve the following problem and compute the probability of the Binomial and Poisson distributions. What is the probability of finding two defects in a Binomial distribution, with a sample size of 30, and probability of 0.2

Astandard deck of cards contains 52 cards. one card is selected from the deck. (a) compute the probability of randomly selecting a seven or king. (b) compute the probability of randomly selecting a seven or king or jack. (c) compute the probability of randomly selecting a queen or spade.

Drag the tiles to the boxes to form correct pairs. not all tiles will be used. match each set of vertices with the type of quadrilateral they form.

Determine if the following statement is true or false. the normal curve is symmetric about its​ mean, mu. choose the best answer below. a. the statement is false. the normal curve is not symmetric about its​ mean, because the mean is the balancing point of the graph of the distribution. the median is the point where​ 50% of the area under the distribution is to the left and​ 50% to the right.​ therefore, the normal curve could only be symmetric about its​ median, not about its mean. b. the statement is true. the normal curve is a symmetric distribution with one​ peak, which means the​ mean, median, and mode are all equal.​ therefore, the normal curve is symmetric about the​ mean, mu. c. the statement is false. the mean is the balancing point for the graph of a​ distribution, and​ therefore, it is impossible for any distribution to be symmetric about the mean. d. the statement is true. the mean is the balancing point for the graph of a​ distribution, and​ therefore, all distributions are symmetric about the mean.