A car manufacturer does performance tests on its cars. During one test, a car starts from rest, and accelerates at a constant rate for 20 seconds. Another car starts from rest three seconds later, and accelerates at a faster constant rate. The equation that models the distance (d) in metres the first car travel travels is: d= 1.16t^2, where t is time, in seconds, after the car starts. The equation for the second car is: d= 1.74(t - 3)^2 a. In the context, what is a suitable domain for the graph of this system?
b. At what time will both cars have driven the same distance?
c. How far will they have driven at this time?

the answer on e2020 is

10

4/5

3/5

4/3

step-by-step explanation:

the answer would be d.

step-by-step explanation:

move all variables to the left side and all constants to the right side

(x−3)^2+(y−1)^2=16

this is the form of a circle. use this form to determine the center and radius of the circle.

( x − h ) 2 + ( y − k ) 2 = r 2

match the values in this circle to those of the standard form. the variable   r   represents the radius of the circle,   h   represents the x-offset from the origin, and   k   represents the y-offset from origin.

r = 4

h = 3

k = 1

the center of the circle is found at   ( h , k ) .

center:   ( 3 , 1 )

these values represent the important values for graphing and analyzing a circle.

center:   ( 3 , 1 ).

radius:   4

hello umm i don't understand your question can you explain it more pls

step-by-step explanation:

step-by-step explanation:

where is the question is there is a formula or is there not one