Evaluate i^15 i^12
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 15 = -i & 12=1

use the pattern : i, -1, -i, 1

Step-by-step explanation:

i =

=

=

=

the pattern just repeats from here

5 = i

6 = -1

7 = -i

8  = 1

9 = i

10 = -1

11 = -i

12  = 1

13 = i

14 = -1

15 = -i

16  = 1

c.

step-by-step explanation:

substitution for (0,1)

y=x^2+4x+1

1=0^2+4(x)0+1

1=0+4(x)0+1

1=4(x)0+1

1=0+1

1=1

substitution for (-3,-2)

y=x+1

-2=-3+1

-2=-2