Low concentrations of EDTA near the detection limit gave the following dimensionless instrument readings: 175, 104, 164, 193, 131, 189, 155, 133, 151, and 176. Ten blanks had a mean reading of 50.0. The slope of the calibration curve is 1.75 x 10^-9 M^-1. a. Estimate the signal detection limit for EDTA.
b. What is the concentration detection limit?
c. What is the lower limit of quantification?

Step-by-step explanation:

From the given information:

The mean of the readings is:

= 157.1

The standard deviation (SD) can be computed by using the expression:

Standard deviation = 28.195

∴

FOr the EDTA complexes;

The signal detection limit = (3*SD) +

= (3*28.195) + 50

= 84.585 + 50

= 134.585

We need to point out that the value of the calibration curve given is too vague and it should be (1.75 x 10^9 M^-1) as oppose to  (1.75 x 10^-9 M^-1)

The concentration of detection limit is:

The lower limit of quantification is:

is should be y = 5x

step-by-step explanation:

correct me if im wrong

dilation scale factor 2: starting with δabc, draw the dilation image of the triangle with a center at the origin and a scale factor of two. notice that every coordinate of the original triangle has been multiplied by the scale factor (x2). dilation with scale factor 2, multiply by 2.