The base of a 40-foot ladder is placed 24 feet away from a wall. What is the height of the wall if the other end of the ladder reaches the top of it?
A. 32 ft
B. 64 ft
C. 16 ft
D. 26 ft

A. 32 ft

Step-by-step explanation:

Pythagoras for right-angled triangles (as that is what this is here - the floor from the base of the ladder to the wall, the wall up to where the ladder ends, and the ladder itself as the Hypotenuse).

c² = a² + b²

with c being the Hypotenuse (the side opposite of the 90 degree angle).

so, we know,

c = 40 ft

a = 24 ft

we are looking for B

=>

40² = 24² + b²

1600 = 576 + b²

1024 = b²

b = 32 ft

c 1 hour

step-by-step explanation:

m = 2e

m = 2 so 2 = 2e

1 = e

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."