The height y of a ball (in feet) is given by the function y= -1/12^2+2+4
and x is the horizontal distance traveled by the ball. How high is the ball when it leaves the child’s hand?

assuming that the problem was actually

-1/12 x ^ 2 + 2x + 4

height = 16

(12,16)

forty feet (40) feet

vertex = -b/2a = -2/(-1/6) = 12

f(12) = - 144/ 12 + 24 + 4 = -12+ 24 + 4   = 16

Step-by-step explanation:

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752