HELP I HAVE TO PASS! What is the average rate of change for this quadratic function for the interval from x=0 to x=2?

A) -4
B) -2
C) 2
B) 4

At X = 0     Y = 10

At X = 2      Y = 6

Rate of  change = change in Y / change in X = -4 / 2 = -2   or B

⊂⊃⊂⊃ω

step-by-step explanation:

i hope this : )

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this