Mathematics, 26.06.2021 05:20 jetblackcap

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What is the solution to this equation? (1/4)^x+1 =32

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Answer from: anthony3913

B. $\displaystyle \frac{-7}{2}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Equality Properties

Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtraction Property of Equality

Algebra I

Exponential Rule [Powering]: $\displaystyle (b^m)^n = b^{m \cdot n}$ Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \bigg( \frac{1}{4} \bigg)^{x + 1} = 32$

Step 2: Solve for x

Rewrite: $\displaystyle \bigg( \frac{1}{2^2} \bigg)^{x + 1} = 2^5$ Exponential Rule [Rewrite]: $\displaystyle (2^{-2})^{x + 1} = 2^5$ Exponential Rule [Powering]: $\displaystyle 2^{-2(x + 1)} = 2^5$ Set: $\displaystyle -2(x + 1)} = 5$ [Division Property of Equality] Divide -2 on both sides: $\displaystyle x + 1 = \frac{-5}{2}$ [Subtraction Property of Equality] Subtract -1 on both sides: $\displaystyle x = \frac{-7}{2}$

Answer from: Quest

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.

Answer from: Quest

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)

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What is the solution to this equation? (1/4)^x+1 =32
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