Prove that
log a² - log b² = log (ab) log (a/b)​

Proof & Step-by-step explanation:

We know that log ab = log a + log b and log a/b = log a - log b, so we substitute that in and get (log ab)(log a/b) = (log a + log b)(log a - log b) = (log a)^2 - (log b)^2.

I hope this helps! If you have any questions, feel free to ask! :)

wholesale price is the initial price before markup. retail price comes after the markup.

a price of 8 bucks that's marked up by 100%   is

formula: initial price + (percent markup in fraction/decimal)(initial price)

8+(1)(8)

8+8

16

retail price is $16.