Mathematics, 25.06.2021 14:50 hernandez09297

(X+2)(X+3)(X+4)=990 I know that x=7 but how do i solve it without substitution?

ie. i don't want to use y=x+3 where 990=(y-1)(y)(y+1)

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(X+2)(X+3)(X+4)=990 I know that x=7 but how do i solve it without substitution?

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(X+2)(X+3)(X+4)=990 I know that x=7 but how do i solve it without substitution? ie. i don't want to use y=x+3 where 990=(y-1)(y)(y+1)

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(X+2)(X+3)(X+4)=990 I know that x=7 but how do i solve it without substitution?

ie. i don't want to use y=x+3 where 990=(y-1)(y)(y+1)