In a Las Vegas casino, gamblers lose a mean of on each roulette game, with a standard deviation of . (Since the standard deviation is quite high with respect to the mean, roulette players often win money on a bet.) Suppose a gambler plays roulette for bets straight. What is the probability that he will be winning after bets

Hello your question is poorly written attached below is the complete question

0.1515

Step-by-step explanation:

Number of bets = 200

mean number of losses  = $0.2

Standard deviation = $2.74

Determine P ( winning after 200 bets )

Average of 200 bets > 0.  i.e. P( X > 0 )

considering normal distribution : μ = -0.2 , б = 2.74 , n = 200

applying Z - distribution

z = 0 - ( - 0.2 ) / ( 2.74 / √200 ) ≈ 1.03

∴ P ( z > 1.03 ) = 1 - P ( z < 1.03 )

                       = 1 - 0.8485  ( value gotten from z-table )

                       = 0.1515

b) 1/3 * 1/5

step-by-step explanation:

each smallest part is 1/15 since the written one is 1/5 and it's divided by 3 equal parts. (1/5 )/3 = 1/15 = 1/3 * 1/5