What is the equation of a line that contains the point (2,-5) and is parallel to the line y=3x-4

y = 3x - 11

Step-by-step explanation:

Parallel lines have the same slope so the relationship of x and y stays the same only the constant, b,  changes

y = 3x + b

plug in point (2, -5) to find "b"

-5 = 3(2) + b

-5 = 6 + b

subtract 6 from both sides

-11 = b

The equation is

y = 3x - 11

(2 , -5) are the points

then y =3x-x,let 4 be x

substitute 2&-5 in the line

-5 =3(2)-x

-5=6-x

-x=6 +5

=11

:x =-11

y=3x - (-11)

y =3x+11

b. an equilateral triangle inscribed in a circle

step-by-step explanation:

we are given the figure of two circles having a triangle inside.

now, we know that,

"when a figure is lying inside an another figure, then the outside figure is known as circumscribed figure and the figure lying inside is referred to as the inscribed figure".

as we see that, the circles are containing the triangle completely.

thus, the circles are the circumscribed figures and the triangle is the inscribed figure.

hence, we get, 'an equilateral triangle is inscribed in a circle'.

true

step-by-step explanation: