For which pairs of functions is (f circle g) (x)? f (x) = x squared and g (x) = StartFraction 1 Over x EndFraction
f (x) = StartFraction 2 Over x EndFraction and g (x) = StartFraction 2 Over x EndFraction
f (x) = StartFraction x minus 2 Over 3 EndFraction and g (x) = 2 minus 3 x
f (x) = one-half x minus 2 and g (x) = one-half x + 2

i really dont know

step-by-step explanation:

51

step-by-step explanation:

73-22=51 the   mass number minus the amount of protons gives you the amount of neutrons

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°