![2x^{99}+3x^{98}+2x^{97}+3x^{96}+.......+2x+3 = [2x^{99}+2x^{97}+...2x]+[3x^{98}+3x^{96}+......3]\\\\=2x*[x^{98}+x^{96}+...+1]+3[x^{98}+x{96}+....1]\\\\= [x^{98}+x^{96}+..+x^{2}.+1](2x+3)\\\\=( [x^{98}+x^{94}+...+x^{2}]+[x^{96}+x^{92}+.......+1])*(2x+3)\\\\=(x^{2}*[x^{96}+x^{92}+.......+1]+[x^{96}+x^{92}+.......+1])*(2x+3)\\\\=[x^{96}+x^{92}+.......+1](x^{2}+1)(2x+3)](/tpl/images/1383/0467/ac8b4.png)
Please answer this 2 question
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Mathematics, 24.06.2021 14:00 beausisugpula
Please answer this 2 question
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The key on a road map has a scale factor of 1.5 inches = 50 miles. the distance between santa fe and albuquerque measures 7.5 inches. the distance between santa fe and taos is 0.75 inches. what is the actual distance between the cities?
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