How many solutions does this linear system have? 03
*
y = 2x-5
- 8x - 4y = -20
one solution: (-2.5, 0)
one solution: (2.5, 0)
no solution
infirhe number of solutions

one solution: (2.5, 0)

Step-by-step explanation:

Given the following system of equations;

y = 2x - 5

-8x - 4y = -20

To find the solution to the equations, we would use the substitution method;

Substituting eqn 1 into eqn 2, we have;

-8x - 4(2x - 5) = -20

-8x - 8x + 20 = -20

-16x + 20 = -20

-16x = -40

x = 40/16

x = 2.5

Next, we would determine the value of y;

y = 2x - 5

y = 2(2.5) - 5

y = 5 - 5

y = 0

-4

step-by-step explanation:

(-4+8)=-(4-8)=-8+4=-4

use formula for the circle a=3.14

step-by-step explanation: