What that two numbers when multiplied give 600 and when added give 59 ​

Step-by-step explanation:

Let the 2 numbers be x and y

From the problem we have that

x * y = 600 and x + y = 59

From x + y = 59 -> x = 59 - y

Plug x = 59 - y to x * y = 600 we have

(59 - y) * y = 600

-> 59y - y^2 = 600

-> -y^2 + 59y - 600 = 0

-> y = or

Then we could plug the answers in and find x because x = 59 - y

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

1; 35 is the ratio

step-by-step explanation: