Mathematics, 23.06.2021 14:00 bks53

The function h(t) = -16t^2 + h, 0 gives the height (in feet) of a ball dropped from a height of h, 0 after t seconds. A ball is dropped from a height of 12 feet. After how many seconds does the ball hit the floor? could someone explain how to solve the equation? I know it's h(t) = -16^2 + 12

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The function h(t) = -16t^2 + h, 0 gives the height (in feet) of a ball dropped from a height of h, 0...