Round to the nearest tenth for 69.08, 43.96, 39.564 please show how to do it ​

69.08 ⇒ nearest tenth

To round 69.08 to the nearest tenth, 0 is in the tenths place and 8 is in the hundredths place.  Since the digit in the hundredths place (8) is greater than  5, add 1 to the digit in the tenths place (0).

1 + 0 = 1, so the digit in the tenths place becomes 1  & the digit in the hundredths place is dropped.

∴ 69.08 ≈ 69.1 (corrected to the nearest tenth)

43.96 ⇒ nearest tenth

To round 43.96 to the nearest tenth, 9 is in the tenths place and 6 is in the hundredths place.  Since the digit in the hundredths place (6) is more than 5, add 1 to the digit in the tenths place (9), add 1 to the digit in the tenths place (9). This will also add 1 to the whole number part and make the fractional part 0.

1 + 9 = 10

∴ 43.96 ≈ 44 (corrected to the nearest tenth)

39.564 ⇒ nearest tenth

To round 39.564 to the nearest tenth, 5 is in the tenths place and 6 is in the hundredths place.  Since the digit in the hundredths place (6) is more than 5, add 1 to the digit in the tenths place (5), add 1 to the digit in the tenths place (5).

1 + 5 = 6, so the digit in the tenths place becomes 6 & the digit in the hundredths and thousandths place is dropped.

∴ 39.564 ≈ 39.6 (corrected to the nearest tenth)

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180