5 (v+1) -v = 4 (v-1) +9

All real numbers are solutions.

Step-by-step explanation:

Our goal is to isolate "v" on one side of the equation. Let's do this step by step.

5(v+1)−v=4(v−1)+9

Step 1: Simplify both sides of the equation.

5(v + 1) − v = 4(v−1) + 9

(5)(v) + (5)(1) + −v = (4)(v) + (4)(−1) + 9(Distribute)

5v + 5 + −v = 4v + −4 + 9

(5v + −v) +(5) = (4v) + (−4 + 9) (Combine Like Terms)

4v + 5 = 4v + 5

4v + 5 = 4v + 5

Step 2: Subtract 4v from both sides.

4v + 5 − 4v = 4v + 5 − 4v

5 = 5

Step 3: Subtract 5 from both sides.

5 − 5 = 5 − 5

0 = 0

This means that all real numbers are solutions.

Any real number could be "v."

Hope this helps, please mark brainliest if possible. Have a great day.

college

the k side

step-by-step explanation:

plese mark mde brainliest!