Suppose players A and B alternate serve from point to point in a modified tie-break in a tennis match. LetpAandpB, respectively, be the probabilities of theirwinning the point on their serve. Can you come up with a back-of-the-envelopecalculation to approximate the exact solution?

answer: the answer is 127 degrees

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

answer: you need the equation in the question so i can answer it

step-by-step explanation: