Given r=3 and a center of (3,5)? Find the equation of the circle in standard and general form.

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(x -3)^2 +(y -5)^2 = 9x^2 +y^2 -6x -10y +25 = 0

Step-by-step explanation:

The standard form equation for a circle of radius r and center (h, k) is ...

  (x -h)^2 +(y -k)^2 = r^2

For radius 3 and center (3, 5), this is ...

  (x -3)^2 +(y -5)^2 = 9 . . . . standard form equation

Expanding this and subtracting the constant on the right gives ...

  x^2 -6x +9 +y^2 -10y +25 -9 = 0

  x^2 +y^2 -6x -10y +25 = 0 . . . . general form equation

step-by-step explanation:

when the line is solid:

it's either < or >

when the line is dashed:

it's either < or >

this > inequality sign means:

greater thanmore thanaboveexceeds

this < inequality sign means:

less thanfewer thanbelow

this > inequality sign means:

greater than/equal tono less thanat leastminimum of

this < inequality sign means:

less than/equal tono more thanat mostmaximum of

about the problem:

since the line is solid, that means it's either < or >

srry i'm not done ! i'll

Ithink it’s a as the answer.