On a coordinate plane, 4 lines are shown. Line L M goes through (negative 5, negative 3) and (0, 3). Line N O goes through (negative 6, negative 5) and (0, 0). Line J K goes through (negative 6, 1) and (0, negative 4). Line P Q goes through (negative 5, 4) and (0, negative 2). Which line is perpendicular to a line that has a slope of Negative five-sixths?

The slope of line LM is perpendicular to the given line.

Step-by-step explanation:

L (- 5, - 3), M (0, 3)

N (- 6, - 5) , O (0, 0)

J (- 6, 1) , K (0, - 4)

Slope of given line = -5/6

Slope of perpendicular line = 6/5

Slope of line LM

Slope of line NO

Slope of line JK

answer: domain and range mean all possible values of x and y that could be substituted to the inequality. a solution means all possible values that make the inequality statement true. so while the range is still all real numbers, the solution is the shaded area, for which y will always be greater than the line of the function.

all the angles opposite to the angle 150 would be 150 and all the angles that are next to 150 are 30 because they equal 180 it you add it up.

step-by-step explanation: