The area of cross section of the large piston in a hydraulic machine is 1m² and that of small piston is 0.5m².calculate the force that must be applied on the small piston to lift a load of 1000N on the large piston

The force that must be applied on the small piston has a magnitude of 500 newtons.

Step-by-step explanation:

By Pascal's Principle, we know that pressure within any point of a closed hydraulic system is the same. Hence, the hydraulic machine can be described by the following model:

(1)

Where:

- Forces applied on the small and large pistons, in newtons.

- Areas of the small and large pistons, in square meters.

If we know that , and , then the force to be applied on the small piston is:

The force that must be applied on the small piston has a magnitude of 500 newtons.

13

step-by-step explanation:

169-1=168

168-3=165

165-5=160

160-7=153

153-9=144

144-11=133

133-13=120

120-15=105

105-17=88

88-19=69

69-21=48

48-23=25

25-25=0

since it took 13times to completely subtract it hence its square root is 13

answer: no

step-by-step explanation:

you are only given the cost not the amount of pounds.