Determine the x and y intercepts for the line 3x – 5y + 15 = 0. Show your work.

Step-by-step explanation:

The x and y intercepts occur when either x or y = 0

For the y intercept, x = 0

3(0) - 5y + 15 = 0

- 5y + 15 = 0                  Subtract 15 from both sides.

-5y = - 15                       Divide by - 5

-5y / -5 = - 15/-5

y = 3

For x intercept, y = 0

3x - 5(0) + 15 = 0

3x + 15 = 0                    Subtract 15 from both sides

3x = - 15                        Divide by 3

3x/3 = - 15/3

x = - 5

xintercept = (-5,0)

yintercept = (0,3)

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b. 18

step-by-step explanation:

so the equation for this is:

ab^2=ac⋅ad

ab being the top length of 6 and ac being the length of 2 and ad being the length of x. let's plug into the equation:

6^2 = 2x

now lets just solve for x:

36 = 2x

18 = x

i hope that !