The length of a rectangle is 18 cm and the width is 6 cm. A similar rectangle has a width of 2 cm. What is the length of the second rectangle? pls help im solving hw ._.

Given:

Two rectangles are similar.

Length of first rectangle = 18 cm

Width of first rectangle = 6 cm

Width of second rectangle = 2 cm

To find:

The length of the second rectangle.

Solution:

We know that the corresponding sides of similar triangles are proportional. So,

Let x be the length of the second rectangle. Then,

Therefore, the length of the second rectangle is 6 cm.

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hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)