MATH QUESTION HELP ME PLS, KINDA URGENT!! I need to resolve this with the elimination method

x +y +z = 13
x–z = −2
−2x +y = 3

how-?

x= 2

y= 7

z= 4

Step-by-step explanation:

Equation 1: x+y+z=13

Equation 2: x-z= -2

Equation 3: -2x+y=3

Add equation 2 and 1

(x+y+z)+(x-z)= 13 -2

2x+y= 11

Add this to equation 3

(-2x+y)+(2x+y)= 11+3

2y= 14

y= 7

Plug in y= 7 to equation 3

-2x+(7)= 3

-2x+7=3

-2x= -4

x= 2

Plug x=2 into equation 2

2-z= -2

4 = z

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation: