According to a survey, 57% of all workers read e-mail while they are in a meeting. Suppose that 19% of those who read e-mail while they are in a meeting write down important notes. Assuming that these figures are true for all workers, if a worker is randomly selected, what is the probability the worker reads e-mail while in meeting and writes important notes

The probability will be "10.83%".

Step-by-step explanation:

According to the question,

Workers read e-mail,

= 57%

= 0.57

Write down important notes,

= 19%

= 0.19

Now,

The probability of worker who reads e-mail while in meeting and writes important notes will be:

=

By putting the values, we get

=

=

= %

4038

step-by-step explanation:

pleaze mark brainliest!

mr. flanders’ class sold 47 doughnuts and   mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations: