Which equation in point-slope form contains the point (4, –1) and has slope 3? y + 1 = 3(x – 4)

y – 4 = 3(x + 1)

y – 1 = 3(x + 4)

y + 4 = 3(x – 1)

y+1=3(x-4)

Step-by-step explanation:

Hi there!

We are given a slope of 3 and a point (4,-1).

We need to find the equation of the line in point-slope form

Point-slope form is given as y-y1=m(x-x1), where m is the slope, and (x1,y1) is a point

We have all of the needed information to substitute into the formula

First, let's label the values of everything to avoid any confusion

m=3

x1=4

y1=-1

now substitute into the formula *remember, the formula has SUBTRACTION, and we have a NEGATIVE number, so we'll end up subtracting a negative*

y--1=3(x-4)

simplify

y+1=3(x-4)

That's it!

Hope this helps :)

, and

for

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

note the following:

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for