Write an equation for the line that passes through E(4, -3) and is parallel to the line 0 = 5x - 7y - 27 Write the equation in general form.

make y the subject first

Step-by-step explanation:

y=5/7(x) -27/7

parallel lines have equal gradient m1=m2

y-y1=m(x-x1)

y-(-3)=5/7(x-4))

y=5/7(x) -20/7 -3

final answer

y=5/7(x) -41/7

d 192

step-by-step explanation:

we find our area to find area we multiply thoses numbers to get our answer so our area is 192

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.