Mr. Ahmed sold his motorcycle to Mr. Saad at a loss of 28%. Mr. Saad spent Rs.1680 on its repairs and sold the motorcycle to Mr. Faiz for Rs.35910, thereby making a profit of 12.5%. Find the cost price of the motorcycle for Mr. Ahmed.

Rs. 42000

Step-by-step explanation:

Let us assume that Mr. Ahmed bought the bicycle for Rs. x, and sold it for Rs. y to Mr. Saad. Since he made a loss of 28%, hence:

y = x - 0.28x = 0.72x

Mr. Saad spent Rs.1680 on its repairs, therefore the total cost price of the motorcycle = 0.72x + 1680

He then sold it for Rs.35910 making a profit of 12.5%. Therefore:

0.72x + 1680 + [0.125(0.72x + 1680)] = 35910

0.81x + 1890 = 35910

0.81x = 34020

x = Rs. 42000

Therefore the cost price of the motorcycle for Mr. Ahmed is Rs. 42000

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

a

step-by-step explanation:

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