A) Model this situation with a linear system: To rent a car, a person is charged a daily rate and a fee for each kilometre driven. When Chena
rented a car for 6 days and drove 320 km, the charge was $286.00. When she rented the same car
for 10 days and drove 900 km, the charge was $605.00.
b) Determine the daily rate and the fee for each kilometre driven.

The daily rate is $ 29 and the fee for each kilometer driven is $ 0.35.

Step-by-step explanation:

Since to rent a car, a person is charged a daily rate and a fee for each kilometer driven, and when Chena rented a car for 6 days and drove 320 km, the charge was $ 286.00, while when she rented the same car for 10 days and drove 900 km, the charge was $ 605.00, to determine the daily rate and the fee for each kilometer driven the following calculation must be performed:

286 = 6 days and 320 km

320/6 = 53,333 km

286/6 = $ 47,666

Thus, the value of 1 day and 53,333 km is $ 47,666.

605 = 10 days and 900 km

900/10 = 90 km

605/10 = $ 60.5

Thus, the value of 1 day and 90 km is $ 60.5.

90 - 53,333 = 36,666

60.5 - 47.666 = 12.833

12,833 / 36,666 = value per kilometer traveled

0.35 = value per kilometer traveled

(286 - (0.35 x 320)) / 6 = X

(286/112) / 6 = X

174/6 = X

29 = X

(605 - (0.35 x 900)) / 10 = X

(605 - 315) / 10 = X

290/10 = X

29 = X

Therefore, the daily rate is $ 29 and the fee for each kilometer driven is $ 0.35.

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step-by-step explanation:

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