It is believed that students who begin studying for final exams a week before the test score differently than students who wait until the night before. Suppose you want to test specifically that students who study earlier have an average score that is less than the average score for students who wait to study. What are the hypotheses for this test if early studiers are group 1 and procrastinators are group 2

H0 : μ1 = μ2

H0 : μ1 < μ2

Step-by-step explanation:

Given :

Early studiers, group 1, mean μ1

Late studiers, group 2 ; mean, μ2

To test the claim that students who study earlier have an average score that is less than the average score for students

The null hypothesis ; there is no difference in average score

H0 : μ1 = μ2

Alternative hypothesis is early studiers means is less than average score of late studiers

H0 : μ1 < μ2

0.16 or 16%

step-by-step explanation:

lets take a coin for example.

if you toss it twice, it has a 1/4 chance of landing on heads both times because 1/2 * 1/2 is 1/4.

with the cards, the chance of picking dog is 0.4. having two people pick one is like picking a card twice in a row. so 0.4 * 0.4 is 0.16, or 16%

the answer is 9.8975

explanation:

when you multiply the "39.59" with the 25% it reduces it and shows its final discounted price. hope this !

step-by-step explanation: