Mathematics, 16.06.2021 20:30 alannaswitzer

The point-slope form of the equation of the line that passes through (-4, -3) and (12, 1) is y– 1 =1/4 (x – 12). What is the standard form of the equation for this line? x - 4y = 8
x - 4y = 2
4x - y = 8
4x - y = 2

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The point-slope form of the equation of the line that passes through (-4, -3) and (12, 1) is y– 1 =1/4 (x – 12). What is the standard form of the equation for this line? x - 4y = 8 x - 4y = 2 4x - y = 8 4x - y = 2 ​

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The point-slope form of the equation of the line that passes through (-4, -3) and (12, 1) is y– 1 =1/4 (x – 12). What is the standard form of the equation for this line? x - 4y = 8
x - 4y = 2
4x - y = 8
4x - y = 2