Two fair dice are tossed. One die is red and one die is green. Calculate the probability that the sum of the numbers on the two dice is an odd number given that the number that shows on the red die is larger than the number that shows on the green die.

1/4

Step-by-step explanation:

The entire sample space for two fair dice is :

Number of faces^2 = 6² = 36

Number of odd sums given that number on red dice is larger than green dice ;

Using the sample space we can count the number of odd sums where the red dice has a larger value than the green dollar dice = 9

Total sample space = 36

Hence, the probability that the sum of the numbers on the two dice is an odd number given that the number that shows on the red die is larger than the number that shows on the green die will be :

(odd sum) / Sample space

9 / 36

= 1/4

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

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step-by-step explanation: