Find the first, fourth, and eighth terms of the sequence
A(n) = −2 ∙ 2x − 1

1st term = -5

4th term = -17

8th term = -33

Step-by-step explanation:

1st term = -2 x (2 x 1) -1

             = -2 x 2 - 1

             = -4 - 1 = - 5

4th term = -2 x (2 x 2) -1

              = -2 x 4 - 1

              = -8 - 1 = - 9

8th term = -2 x (2 x 8) - 1

              = -2 x 16 - 1

              = -32 - 1 = - 33

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

step-by-step explanation:

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