Please tell me the area and attach work the most important part is work since I’m confused on subtracting the side lengths

The area is 288 feet

Step-by-step explanation:

So the best way to solve problems like this is to think about the parts of the object like different things, and iscolating them.

We see that the length of the rectangle is 21, and the width is 13.

Ignore the 5 and 16, since they tell you what you neeed to know about the other smaller rectangle.

So lets just use the formula for area of a rectnagle, which is l*w, using the 21 and 13 values above:

21*13= 273

Now lets look at the second part.

I think this is the part you were confused with, so I will go into detail on how we find the area of this part of the rectangle

We see that there is a 16...However, we already know that the width is 13. So how is this? The 16 includes both the width of the rectangle and of the smaller piece.

Since we already know that the width of the rectangle is 13, but the small segment makes it 16, we can subtract the total wifth by the width of the rectangle, which will find us the width of the segment:

16-13=3

So the width is 3.

This is not what we do with the 21 and 5. When we look at the segment, we see that the 5 covers all of it, and does not cover any of the rectangle's length. This basicallly means that the 5 length is only for the segment, so this is considered our length.

Now we can use this to figure out the segments area:

3*5=15

Now, since we need to find the combined area of the both the segment and the rectangle, we need to add them together:

273+15=288

So the area is 288 in total.

Hope this helps!

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

step-by-step explanation:

im not sure what the answer is