f(x)=(5x+3)(x−2)(3x+7)(x+5)f, left parenthesis, x, right parenthesis, equals, left parenthesis, 5, x, plus, 3, right parenthesis, left parenthesis, x, minus, 2, right parenthesis, left parenthesis, 3, x, plus, 7, right parenthesis, left parenthesis, x, plus, 5, right parenthesis has zeros at x=-5x=−5x, equals, minus, 5, x=-\dfrac{7}{3}x=− 3 7 ​ x, equals, minus, start fraction, 7, divided by, 3, end fraction, x=-\dfrac{3}{5}x=− 5 3 ​ x, equals, minus, start fraction, 3, divided by, 5, end fraction, and x=2x=2x, equals, 2. What is the sign of fff on the interval -\dfrac{7}{3}

it has the same slope and a different y-intercept

hope this : )

where are the graphs?

step-by-step explanation:

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.