Place the digits 1, 2, 3, 4, 5, and 6 in the circles below so that the sum of the three numbers on each side of the triangle is 12. Hint: There are a limited number of possible configurations. ​

Determine whether the points (–3,–6) and (2,–8) are in the solution set of the system of inequalities below. x ? –3 y < 5? 3x + 2 a. the point (–3,–6) is not in the solution set, and the point (2,–8) is in the solution set. b. neither of the points is in the solution set. c. the point (–3,–6) is in the solution set, and the point (2,–8) is not in the solution set. d. both points are in the solution set.

[15 points, algebra 2]simplify the complex fraction and find the restrictions.

What is the quotient? x+5/ 3x²+4x+5 © 3x2 – 11 + x + s 3x – 11 + 60 x + 5 o 3x2 - 11 - 50 x + 5 3x – 11 - - x + 5