What is the vertex of the graph of the following equation? y = x^2 + 2x-3

vertex = (- 1, - 4 )

Step-by-step explanation:

Given a parabola in standard form

y = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the vertex is

x = -

y = x² + 2x - 3 ← is in standard form

with a = 1, b = 2 , then

x = - = - 1

Substitute x = - 1 into the equation for corresponding value of y

y = (- 1)² + 2(- 1) - 3 = 1 - 2 - 3 = - 4

vertex = (- 1, - 4 )

the solution is 12x-6y