F (x) =x^2-6x+4 how do i find the vertex ?

(3, -5)

Step-by-step explanation:

So, there are three steps in finding the vertex.

We need to first find a, b and c. a is the x^2 coefficent, b is the x cofficent, and c is the number value. In this case:

a=1, b=-6, and c=4

To find the x value of the vertex, plug in a and b into the formula:

-b/2a = x coord of vertex:

-*-6/2*1

=

6/2

=

3

So the x coordinates of the vertex is 3.

To find the y cooridnates, plug in 3 into the orginal equation:

=

=

So -5 is the y coordinates of the vertex.

(3, -5)

Hope this helps!

Going over steps:

Step 1 - Find values a b and c: a=x^2 coefficent. b=x coefficent. c=number

Step 2 - Plug in a and b into -b/2a

Step 3 - Plug in x into equation

y = - 6

step-by-step explanation:

given the point (- 2, y) lies on the graph then it is a solution of it's equation.

substitute x = - 2 into the equation for value of y

y = 3(- 2) = 3 × - 2 = - 6

the point on the graph is (- 2, 6)

addition

step-by-step explanation: