PLEASE HELP ME, THE QUESTION IS ABOUT A SHIRT BEING LAUNCHED AND CAUGHT AT A DIFFERENT HEIGHT!! In between periods of the hockey game, the marketing department uses a slingshot to launch t-shirts into the crowd. The release point is 5 feet above the surface of the ice, and the shirts are shot with an initial velocity of 52 ft/s. Suppose a shirt is caught 17 ft above the ice on its way down by a fan in the crowds. How long is the shirt in the air? ie; how many seconds after launching is the t-shirt at 17 feet?
formula: h=-16t^2+vt+c

answer: plz put a pic in so i can answer it

step-by-step explanation:

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240

step-by-step explanation:

f(gx)=f(1/x+2)

=(1/x+2)+2

=(1+2x)/2+2

=(1+2x+4)/2

= (2x+5)/2