Math question part 2 show work thanks Jim !!

Part (b)

The scale 1 cm = 2 m means we'll multiply whatever the cm distance is by 2 to get the meter distance in real life.

The shed is 3 cm by 3 cm on paper. It corresponds to 6 meters by 6 meters in real life.

The cement pad is 6 meters by 10 meters in real life because it's originally 3 cm across and 5 cm vertical. We double each dimension as done before, and replace "cm" with "m".

The hot tub is a circle so we don't get an exact measurement here. But we can determine a good estimate. It appears it's 2 cm across and 2 cm vertical. So that corresponds to 4 meters by 4 meters

Part (c)

On paper, the distance is 4.5 cm since we count out 4 full squares plus half a square when going a horizontal distance from the cement pad to the pool.

Therefore, the distance in real life is 9 meters

1 cm = 2 m

4.5*(1 cm) = 4.5*(2 m)

4.5 cm = 9 m

Part (d)

The flowerbed on paper has sides of 4 cm and 6 cm. Use the pythagorean theorem to find the hypotenuse is approximately 7.21 cm.

Double each dimension, and replace the 'cm' with 'm'

The side lengths of the actual flowerbed is 8 meters, 12 meters, 14.42 meters. That last value being approximate.

Add up the values to get the perimeter: 8+12+14.42 = 34.42

perimeter = 34.42 meters (approximate)

use substitution to solve each system of equations. y = x + 5 3x + y = 25 62/87,21 y = x + 5 3x + y = 25 substitute x + 5 for y in the second equation. substitute the solution for x into either equation to find y. the solution is (5, 10)

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answer: i'm not sure

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