A book that is 13 inches tall is leaning against the edge of a wall. If the bottom of the book is 5 inches from the wall, how far up the wall is the top of the book?

Length of the book (hypotenuse) = 13 inches

Distance of the book from the foot of the wall (base) = 5 inches

Length of the book on the wall (perpendicular ''").

By Pythagoras theorem, we have

(Perpendicular)² + (Base)² = (Hypotenuse)²

  + (5 in) ² = (13 in)²

+ 25 in² = 169 in²

  = 169 in² - 25 in²

  = 144 in²

  =

  =

  =

  = 12 in

Therefore, the height of the book on the wall is 12 inches.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)