Find the value of x in the isosceles triangle shown below.

22.18 = x

Step-by-step explanation:

a^2 + (b)^2 = (x/2)^2

a = sqrt(74)

b = 7

x/2 = ?

(74)[^1/2]^2 = 74            

b^2 = 7^2 = 49

74 + 49 = (x/2)^2       Substitute into a^2 + b^2 = c^2

123 = (x/2)^2              Combine like terms

(123^0.5) = x/2           Take the square root of both sides.

11.09 = x/2                  Multiply both sides by 2

11.09*2 = x

22.18 = x                     The full length of the base of the triangle is 22.18

C

Step-by-step explanation: We only need to find the value of one of the x so just use Pythagorean theorem but simplified to do it in one step which is sqrt(4^2+6^2) which gives us sqrt(52).

x=6 and x=3

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