![(1) \: \: \sqrt[3]{5} \times \sqrt[3]{ \frac{2}{5} } \times \frac{ \sqrt[3]{64} }{ \sqrt[3]{3} } \times \frac{ \sqrt[6]{9} }{ \sqrt[3]{2} }](/tpl/images/1373/4283/d3c89.png)
![\sqrt[3]{5} \times \sqrt[3]{ \frac{2}{5} } = \sqrt[3]{5 \times \frac{2}{5} } = \sqrt[3]{2}](/tpl/images/1373/4283/cb7dd.png)
![\sqrt[3]{64} = 4](/tpl/images/1373/4283/c9fe6.png)
![\sqrt[6]{9} =({( {3})^{2} })^{ \frac{1}{6} } = \sqrt[3]{3}](/tpl/images/1373/4283/8f5e2.png)
![\sqrt[3]{2} \times \frac{4}{ \sqrt[3]{3} } \times \frac{ \sqrt[3]{3} }{ \sqrt[3]{2} }](/tpl/images/1373/4283/c5679.png)
![\sqrt[3]{5} \times \sqrt[3]{ \frac{2}{5} } \times \frac{ \sqrt[3]{64} }{ \sqrt[3]{3} } \times \frac{ \sqrt[6]{9} }{ \sqrt[3]{2} } = 4](/tpl/images/1373/4283/8fa54.png)
Please help I this sum...It’s prove that...
Went with explanation...
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Mathematics, 14.06.2021 06:20 meli82
Please help I this sum...It’s prove that...
Went with explanation...
Will give Brainliest...
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